The correct answer for this question is 1300 mg/dL. The laboratorian performed a 1:4 dilution by adding 0.25
mL (or 250 microliters) of patient sample to 750 microliters of diluent. This creates a total volume of 1000
microliters. So, the patient sample is 250 microliters of the 1000 microliter mixed sample, or a ratio of 1:4.
Therefore, the result given by the chemistry analyzer must be multiplied by a dilution factor of 4. 325 mg/dL x
4 = 1300 mg/dL.
After experiencing extreme fatigue and polyuria, a patient's basic metabolic panel is analyzed in the
laboratory. The result of the glucose is too high for the instrument to read. The laboratorian performs a dilution
using 0.25 mL of patient sample to 750 microliters of diluent. The result now reads 325 mg/dL. How should
the techologist report this patient's glucose result?