What happens when you attempt to compile and run the following code? #include #include #include #include using namespace std; templatestruct Out { ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< v1(10); generate_n(v1.begin(), 10, Sequence(1)); random_shuffle(v1.rbegin(), v1.rend()); sort(v1.begin(), v1.end(), great()); for_each(v1.begin(), v1.end(), Out(cout));cout<
What happens when you attempt to compile and run the following code? #include #include #include using namespace std; int main () { int t[] = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 }; vector v1(t, t + 10); deque d1(v1.begin(), v1.end());deque d2; d2 = d1; d2.insert(d1.rbegin(), 10); for(int i = 0; i
What happens when you attempt to compile and run the following code? #include #include #include #include using namespace std; void myfunction(int i) { cout << " " << i; } struct sequence { int val,inc; sequence(int s, int i):val(s),inc(i){} int operator()(){ int r = val; val += inc; return r; } }; int main() { vector v1(10);fill(v1.begin(), v1.end(), sequence(1,1)); for_each(v1.begin(), v1.end(), myfunction); return 0; }Program outputs:
What happens when you attempt to compile and run the following code? #include #include #include #include using namespace std; class B { int val; public: B(int v):val(v){} int getV() const {return val;} bool operator > (const B & v) const { return val>v.val;} }; ostream & operator <<(ostream & out, const B & v) { out<struct Out { ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< d1(t, t+10); sort(d1.begin(), d1.end(), greater()); pair ::iterator, deque::iterator > result = equal_range(d1.begin(), d1.end(),B(20), greater()); for_each(result.first, result.second, Out(cout));cout<