Free C++ Institute CPP-22-02 Exam Questions

Absolute Free CPP-22-02 Exam Practice for Comprehensive Preparation 

  • C++ Institute CPP-22-02 Exam Questions
  • Provided By: C++ Institute
  • Exam: CPP - C++ Certified Professional Programmer
  • Certification: C++ Certified Professional Programmer
  • Total Questions: 230
  • Updated On: Apr 14, 2026
  • Rated: 4.9 |
  • Online Users: 460
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  • Question 1
    • What happens when you attempt to compile and run the following code? #include  #include  #include  using namespace std; class B { int val; public: B(int v):val(v){} int getV() const {return val;} bool operator < (const B & v) const { return valstruct Out { ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< v1(10,0); sort(t1, t1+5); sort(t2, t2+5); set_union(t1,t1+5,t2,t2+5,v1.begin()); for_each(v1.begin(), v1.end(), Out(cout));cout<

Answer: A
  • Question 2
    • What happens when you attempt to compile and run the following code? #include #include  #include  using namespace std; int main(){ int second[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 10 }; string first[] = {"three", "four", "two", "one", "six","five", "seven", "nine","eight"," ten"}; map m; for(int i=0; i<10; i++) { m.insert(pair(second[i],first[i])); } if (m[11] == "eleven") { cout<<"eleven "; } for(map::iterator i=m.begin();i!= m.end(); i++) { cout<second<<" "; } cout<

  • Answer: A
  • Question 3
    • What happens when you attempt to compile and run the following code? #include  #include  #include  using namespace std; templatestruct Out { ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< d1(t, t+10); sort(d1.begin(), d1.end()); deque::iterator it = upper_bound(d1.begin(), d1.end(), 4); for_each(it, d1.end(), Out(cout));cout<

  • Answer: A
  • Question 4
  • Question 5
    • What happens when you attempt to compile and run the following code? #include  #include #include  #include  using namespace std; class B { int val; public: B(int v):val(v){} int getV() const {return val;} bool operator > (const B & v) const { return val>v.val;} }; ostream & operator <<(ostream & out, const B & v) { out<struct Out { ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< d1(t, t+10); sort(d1.begin(), d1.end(), greater()); pair ::iterator, deque::iterator > result = equal_range(d1.begin(), d1.end(),B(20), greater()); for_each(result.first, result.second, Out(cout));cout<

  • Answer: B
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