Free Ruby Association Ruby-Programmer-Gold Exam Questions
Absolute Free Ruby-Programmer-Gold Exam Practice for Comprehensive Preparation
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Ruby Association Ruby-Programmer-Gold Exam Questions
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Provided By: Ruby Association
- Exam: Ruby Association Certified Ruby Programmer Gold version 3
- Certification: Ruby Association Certified
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Total Questions: 160
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Updated On: Jul 23, 2026
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Rated: 4.9 |
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Online Users: 320
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Question 1
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In Ruby programming, the correct use and understanding of operators is essential. Analyze the following Ruby code snippet:
a = 8b = 4result1 = a != bresult2 = a & b == 4result3 = (a * 2) / b Based on this code, which two of the following statements are true regarding the use and precedence of the operators?
Answer: B,D
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Question 2
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Review the following Ruby code snippet:
def execute_operations(operations) operations.each do |operation| result = send(operation) break result if result == :error endend def operation1 :successend def operation2 :errorend def operation3 :successend result = execute_operations([:operation1, :operation2, :operation3]) What will be the value of result after executing this code?
Answer: B
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Question 3
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In Ruby, the use of blocks is a fundamental concept for iterating over collections and executing code repeatedly. Examine the following Ruby code snippet:
numbers = [1, 2, 3, 4, 5]sum = 0numbers.each { |number| sum += number }doubled = numbers.map { |number| number * 2 } Based on this code, which two of the following statements are true regarding the use and functionality of blocks?
Answer: C,E
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Question 4
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In Ruby, the understanding of operators and their precedence is crucial for writing correct and efficient code. Consider the following Ruby code snippet:
a = 10b = 3result1 = a + b * 2result2 = (a + b) % 3result3 = a ** b / 2 Based on this code, which two of the following statements are true regarding the use of operators and their precedence?
Answer: A,E
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Question 5
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Review the following Ruby code snippet in the context of class inheritance and method access control:
class Productdef initialize(name, price)@name = name@price = priceendprivatedef price@priceendendclass Electronic < Productdef discount_amount(discount_percentage)price * discount_percentage / 100.0enddef discounted_price(discount_percentage)price - discount_amount(discount_percentage)endendelectronic_item = Electronic.new("Laptop", 1000)result = electronic_item.discounted_price(20)What will be the value of result?
Answer: B
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